If it's not what You are looking for type in the equation solver your own equation and let us solve it.
64g^2-25=0
a = 64; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·64·(-25)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*64}=\frac{-80}{128} =-5/8 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*64}=\frac{80}{128} =5/8 $
| 5x-10+2x-3+4x+6=180 | | 15-2x=7.667 | | x–23=18 | | 8r-4r+5=7r+5-r | | h-3=17 | | 13-2m=m+4 | | 4.25=8+2.5y | | 15x=(×-1) | | 5x-12+3x-15+2x+17=180 | | 2/3s-5/3=5/6+1 | | 39x+4=37+x | | A=(2*y+1)*(y+3) | | 10.71-9.8s=-9.6s+14.01 | | 3(2x+6)=-21+15 | | -11x-15=10-6x | | 8+b/4-3=-10 | | -15=5(1-m)-2(1-m) | | d-27=4 | | -17-12j=-20j+7 | | 2(x-8)+2=1x-3 | | –6p+17=–7p+2 | | 1x+18=36 | | 6x+2)=(3x+7) | | -1(3x+8)=6x-23 | | 29=9x+5-4x | | 5.5x-13.4=25.1 | | 5x+1+x+16+2x+11=180 | | 6m=51 | | 4m+11-7m+3m+3=14m+14 | | 3-(2.7/9)=n | | 9(x-8)+20=9x-52 | | 22(3x+1)-x=17 |